Transferring heat energy generated by power resistors. So I thought to myself, "I have 12v * 6a = 72w power supply, if I'm using 4 x 10w resistors 72 watts would be too much for them." Related Resources https://electrical-engineering-portal.com/resistive-heating-explained-in-details If a resistor has a power rating of 1W, then we should not feed more than 1W to the resistor. I dissipate the heat with a 12V PC fan . A resistors power dissipation must be further reduced if it's effected by near by components or resistors that are radiating heat which would effect the surrounding ambient temperature [of the resistor being effected]. How should they be configured to produce my needed heat. In some cases, however, Joule heating is exploited as a source of heat, such as in a toaster or an electric heater. Resistors will heat up as they slow down the current running through the circuit. The power dissipated in a resistor goes into heating the resistor; this is know as Joule heating. A thermistor is a type of resistor that varies its resistance with temperature. If I stop the current when the correct temperature is reached, the temperature keeps on climbing because some heat is still stored in the resistors heatsink, and I overshoot the target temperature by 2°C for a short amount of time. The problem I have with these resistors is that the inertia is too high. If I wanted to build a circuit that would turn on a fan in the attic when it reaches a … In many cases, Joule heating is wasted energy. If they are getting very hot to the touch and start to boil or smell then you need to get higher power resistors. Technically I don’t like to use the terms power loss. value. The electric company bills not for power but for energy, using units of kilowatt-hours. Power dissipated by a resistor is P = I^2 x R or P= V^2/R both derivations of P = I x V and of V= I x R (Ohm’s law). 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